Difference between revisions of "1987 AJHSME Problems/Problem 3"
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==Solution 2== | ==Solution 2== | ||
− | + | Find that | |
− | < | + | <cmath>(81+83+85+87+89+91+93+95+97+99) = 5 \cdot 180</cmath> |
− | + | Thus | |
+ | <cmath>\begin{align*} | ||
+ | 2(5 \cdot 180) &= 10 \cdot 180\\ | ||
+ | &= 1800 & \text{ Thus (E) is the correct answer} | ||
+ | \end{align*}</cmath> | ||
==Solution 1== | ==Solution 1== |
Revision as of 19:38, 23 November 2016
Contents
Problem
Solution 2
Find that Thus
Solution 1
Find that Thus
See Also
1987 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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