Difference between revisions of "2015 UNCO Math Contest II Problems/Problem 1"
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== Solution == | == Solution == | ||
| + | Call the smallest integer <math>x</math>. We can express the sum as <math>(x) + (x + 1) + (x + 2)</math>. Solving, we get <math>(x) + (x + 1) + (x + 2) = 54 \implies 3x + 3 = 54 \implies 3x = 51 \implies x = \boxed{17}</math>. | ||
== See also == | == See also == | ||
Latest revision as of 15:38, 26 November 2016
Problem
The sum of three consecutive integers is 
. What is the smallest of the three integers?
Solution
Call the smallest integer 
. We can express the sum as 
. Solving, we get 
.
See also
| 2015 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNCO Math Contest Problems and Solutions | ||
