Difference between revisions of "1987 AHSME Problems/Problem 1"

Latest revision as of 17:33, 23 April 2017

$(1+x^2)(1-x^3)$ equals

$\text{(A)}\ 1 - x^5\qquad \text{(B)}\ 1 - x^6\qquad \text{(C)}\ 1+ x^2 -x^3\qquad \\ \text{(D)}\ 1+x^2-x^3-x^5\qquad \text{(E)}\ 1+x^2-x^3-x^6$

We multiply: $(1+x^2)(1-x^3) = 1 - x^3 + x^2 - x^5$ . Thus the answer is $\boxed{D}$ . -slackroadia

1987 AHSME (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

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 ==Solution==
-We multiply: <math>(1+x^2)(1-x^3) = 1 - x^3 + x^2 - x^5</math>. Thus the answer is <math>\boxed{D}</math>
+We multiply: <math>(1+x^2)(1-x^3) = 1 - x^3 + x^2 - x^5</math>. Thus the answer is <math>\boxed{D}</math>.
+-slackroadia
 == See also ==