Difference between revisions of "Circumradius"
m (→Right triangles) |
m (→Equilateral triangles) |
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Line 78: | Line 78: | ||
C=intersectionpoint(arc(A,1,0,90),arc(B,1,90,180)); | C=intersectionpoint(arc(A,1,0,90),arc(B,1,90,180)); | ||
draw(A--B--C--cycle); | draw(A--B--C--cycle); | ||
− | I= | + | I=circumcenter(A,B,C); |
draw(circumcircle(A,B,C)); | draw(circumcircle(A,B,C)); | ||
label("$C$",I,E); | label("$C$",I,E); | ||
dot(I); | dot(I); | ||
+ | label("$s$",A--B,S); | ||
+ | label("$s$",A--C,N); | ||
+ | label("$s$",B--C,N); | ||
</asy> | </asy> | ||
Revision as of 19:02, 1 August 2017
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The circumradius of a cyclic polygon is the radius of the cirumscribed circle of that polygon. For a triangle, it is the measure of the radius of the circle that circumscribes the triangle. Since every triangle is cyclic, every triangle has a circumscribed circle, or a circumcircle.
Contents
[hide]Formula for a Triangle
Let and denote the triangle's three sides, and let denote the area of the triangle. Then, the measure of the circumradius of the triangle is simply . Also,
Proof
We let , , , , and . We know that is a right angle because is the diameter. Also, because they both subtend arc . Therefore, by AA similarity, so we have or However, remember that area , so . Substituting this in gives us and then bash through algebra to get and we are done.
--Nosaj 19:39, 7 December 2014 (EST)
Formula for Circumradius
Where is the Circumradius, is the inradius, and , , and are the respective sides of the triangle and is the semiperimeter. Note that this is similar to the previously mentioned formula; the reason being that .
Euler's Theorem for a Triangle
Let have circumcenter and incenter .Then
Proof
Right triangles
The hypotenuse of the triangle is the diameter of its circumcircle, and the circumcenter is its midpoint, so the circumradius is equal to half of the hypotenuse of the right triangle.
Equilateral triangles
where is the length of a side of the triangle.
If all three sides are known
And this formula comes from the area of Heron and .
If you know just one side and its opposite angle