Difference between revisions of "Orthocenter"
(Replaced Ceva proof with more elegant Euler line proof) |
|||
Line 1: | Line 1: | ||
− | The '''orthocenter''' of a [[triangle]] is the point of intersection of its [[altitude]]s. | + | The '''orthocenter''' of a [[triangle]] is the point of intersection of its [[altitude]]s. It is conventionally denoted as <math>\displaystyle H</math>. |
+ | |||
− | |||
[[Image:Orthoproof1.PNG|center]] | [[Image:Orthoproof1.PNG|center]] | ||
− | |||
− | + | == Proof of Existence == | |
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | |||
− | + | ''Note: The orthocenter's existence is a trivial consequence of the [[trigonometric version of Ceva's Theorem]]; however, the following proof, due to [[Leonhard Euler | Euler]], is much more clever, illuminating and insightful.'' | |
− | < | + | Consider a triangle <math>\displaystyle ABC</math> with [[circumcenter]] <math>\displaystyle O</math> and [[centroid]] <math>\displaystyle G</math>. Let <math>\displaystyle A'</math> be the midpoint of <math>\displaystyle BC</math>. Let <math>\displaystyle H</math> be the point such that <math>\displaystyle G</math> is between <math>\displaystyle H</math> and <math>\displaystyle O</math> and <math>\displaystyle HG = 2 HO</math>. Then the triangles <math>\displaystyle AGH</math>, <math>\displaystyle A'GO</math> are [[similar]] by angle-side-angle similarity. It follows that <math>\displaystyle AH</math> is parallel to <math>\displaystyle OA'</math> and is therefore perpendicular to <math>\displaystyle BC</math>; i.e., it is the altitude from <math>\displaystyle A</math>. Similarly, <math>\displaystyle BH</math>, <math>\displaystyle CH</math>, are the altitudes from <math>\displaystyle B</math>, <math>\displaystyle {C}</math>. Hence all the altitudes pass through <math>\displaystyle H</math>. Q.E.D. |
− | This | + | This proof also gives us the result that the orthocenter, centroid, and circumcenter are [[collinear]], in that order, and in the proportions described above. The line containing these three points is known as the [[Euler line]], after the person to whom this proof is due. |
Revision as of 20:03, 25 August 2006
The orthocenter of a triangle is the point of intersection of its altitudes. It is conventionally denoted as .
Proof of Existence
Note: The orthocenter's existence is a trivial consequence of the trigonometric version of Ceva's Theorem; however, the following proof, due to Euler, is much more clever, illuminating and insightful.
Consider a triangle with circumcenter and centroid . Let be the midpoint of . Let be the point such that is between and and . Then the triangles , are similar by angle-side-angle similarity. It follows that is parallel to and is therefore perpendicular to ; i.e., it is the altitude from . Similarly, , , are the altitudes from , . Hence all the altitudes pass through . Q.E.D.
This proof also gives us the result that the orthocenter, centroid, and circumcenter are collinear, in that order, and in the proportions described above. The line containing these three points is known as the Euler line, after the person to whom this proof is due.