2019 AMC 10A Problems/Problem 2
Problem
What is the hundreds digit of 
Solution
The last three digits of 
for all 
is 
, because there are at least three 2s and three 5s in its prime factorization. Because 
, The answer is \boxed{(A) 0}$.
See Also
| 2019 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
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| All AMC 10 Problems and Solutions | ||
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