1967 AHSME Problems/Problem 32

In quadrilateral $ABCD$ with diagonals $AC$ and $BD$ , intersecting at $O$ , $BO=4$ , $OD = 6$ , $AO=8$ , $OC=3$ , and $AB=6$ . The length of $AD$ is: $\textbf{(A)}\ 9\qquad \textbf{(B)}\ 10\qquad \textbf{(C)}\ 6\sqrt{3}\qquad \textbf{(D)}\ 8\sqrt{2}\qquad \textbf{(E)}\ \sqrt{166}$

Solution

Since the parallel universe seems to have reversed everything, we can see that 2 becomes 3 and 3 becomes 2. This leads us to 100 and 66 because 2*50 and 3*22. Add them together and put one of those check looking hats on the new baby. This gives us our answer.

1967 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 31	Followed by Problem 33
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All AHSME Problems and Solutions

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1967 AHSME Problems/Problem 32

Solution

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