2013 AMC 8 Problems/Problem 4

Problem

Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends paid an extra $2.50 to cover her portion of the total bill. What was the total bill?

$\textbf{(A)}\ \text{\textdollar}120\qquad\textbf{(B)}\ \text{\textdollar}128\qquad\textbf{(C)}\ \text{\textdollar}140\qquad\textbf{(D)}\ \text{\textdollar}144\qquad\textbf{(E)}\ \text{\textdollar}160$

Solution

Since Judi's 7 friends had to pay 2.50 extra each, to cover the total amount that Judi should have paid, we can multiply 2.50 by 7, which is equal to 17.50. We can now tell that 17.50 is the amount that each of her friends needed to pay, such that Judi didn't forget her money. So, we multiply 17.50 by 8 which is, (C) 140, the total amount of the meal.

Solution 2

Say $m$ is the total amount needed to be paid. At the beginning, each person was supposed to pay $$\frac{m}{8}$ . But since Judi forgot her money, we have to add $$\frac{m}{8}$ to $$2.50$ to get the amount of money each of the $7$ friends have to pay. Multiply $$\frac{m}{8} + 2.50$ by $7$ to get $$\frac{7m}{8} + 140$ . We can set that equal to $m$ because after we multiply by $7$ we have the total amount needed to be paid. Solving for $m$ we have our answer, $\boxed{\text{(C)} 140}$ .

Video Solution

https://youtu.be/lvaWrFwW6BM ~savannahsolver

2013 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 3	Followed by Problem 5
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Page

Toolbox

Search

2013 AMC 8 Problems/Problem 4

Contents

Problem

Solution

Solution 2

Video Solution

See Also