1999 AHSME Problems/Problem 15
Problem
Let be a real number such that
. Then
Solution 1 (Fastest)
, so
.
Solution 2 (Alternate)
Note that , and since
, let
and multiply the two, we get
, which equals
. This equates to
. Thus, \boxed{\textbf{(E)}\ 0.5}$.
See Also
1999 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
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