1994 AJHSME Problems/Problem 5

Problem

Given that $\text{1 mile} = \text{8 furlongs}$ and $\text{1 furlong} = \text{40 rods}$ , the number of rods in one mile is

$\text{(A)}\ 5 \qquad \text{(B)}\ 320 \qquad \text{(C)}\ 660 \qquad \text{(D)}\ 1760 \qquad \text{(E)}\ 5280$

Solution

$(1\ \text{mile}) \left( \frac{8\ \text{furlongs}}{1\ \text{mile}} \right) \left( \frac{40\ \text{rods}}{1\ \text{furlong}} \right) = \boxed{\text{(B)}\ 320}$

1994 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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1994 AJHSME Problems/Problem 5

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