2003 AMC 10B Problems/Problem 20
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Problem
In rectangle and . Points and are on so that and . Lines and intersect at . Find the area of .
Solution
because The ratio of to is since and from subtraction. If we let be the height of
\begin{align*}\frac{2}{5} &= \frac{h-3}{h}\\ 2h &= 5h-15\\ 3h &= 15\\ h &= 5 (Error compiling LaTeX. Unknown error_msg)
The height is so the area of is .
See Also
2003 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
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