2013 AMC 8 Problems/Problem 17

Revision as of 08:30, 27 November 2013 by Flyrain (talk | contribs) (Solution)

Problem

The sum of six consecutive positive integers is 2013. What is the largest of these six integers?

$\textbf{(A)}\ 335 \qquad \textbf{(B)}\ 338 \qquad \textbf{(C)}\ 340 \qquad \textbf{(D)}\ 345 \qquad \textbf{(E)}\ 350$

Solution

The mean of these numbers is $\frac{\frac{2013}{3}}{2}=\frac{671}{2}=335.5$. Therefore the numbers are $333, 334, 335, 336, 337, 338$, so the answer is $\boxed{\textbf{(B)}\ 338}$

See Also

2013 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
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