1997 PMWC Problems/Problem I10

Problem

Mary took $24$ chickens to the market. In the morning she sold the chickens at $\textdollar 7$ each and she only sold out less than half of them. In the afternoon she discounted the price of each chicken but the price was still an integral number in dollar. In the afternoon she could sell all the chickens, and she got totally $\textdollar 132$ for the whole day. How many chickens were sold in the morning?

Solution

Let $A$ be the number of chickens she sold before the discount and $B$ be the number of chickens sold after the discount. Let $c$ be the price of one chicken after the discount.

$A+B=24$

$7A+cB=132$

$(7-c)(A)=132-24c$

So $c$ is less than $5$ . We make a table of $A$ and $c$ :

$c$ | $A$

$5$ | $6$

$4$ | $18$

So $c$ must equal $5$ , since when $c$ decreases, $A$ increases.

$A=6$ .

1997 PMWC (Problems)
Preceded by Problem I9	Followed by Problem I11
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10

Page

Toolbox

Search

1997 PMWC Problems/Problem I10

Problem

Solution

See Also