1997 PMWC Problems/Problem T9
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Contents
Problem
Find the two -digit numbers which become nine times as large if the order of the digits is reversed.
Solution
The pair of numbers are and
.
Notice that the sum of two numbers is 10 times of the smaller one. Let the smaller one be , the large one becomes
. Then we have
=
+
.
It's obvious that
and
. Comparing the digits, we have
,
,
, and
.
Mistake Above Fix
The actual two numbers are , as mentioned above, but the second number is
, not
.
Someone please fix.
See Also
1997 PMWC (Problems) | ||
Preceded by Problem T8 |
Followed by Problem T10 | |
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 |