1991 AJHSME Problems/Problem 20
Contents
Problem
In the addition problem, each digit has been replaced by a letter. If different letters represent different digits then
Solution
From this we have
Clearly,
. Since
,
Thus,
and
. From here it becomes clear that
and
.
Solution
Using logic, , therefore
(from the carry over)
.
so b+a=9
A+1=3
Thus, and
. From here it becomes clear that
and
.
See Also
1991 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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