2024 AMC 8 Problems

Revision as of 22:00, 20 January 2024 by Rainier2020 (talk | contribs) (Problem 17)
2024 AMC 8 (Answer Key)
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Instructions

  1. This is a 25-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct.
  2. You will receive 1 point for each correct answer. There is no penalty for wrong answers.
  3. No aids are permitted other than plain scratch paper, writing utensils, ruler, and erasers. In particular, graph paper, compass, protractor, calculators, computers, smartwatches, and smartphones are not permitted. Rules
  4. Figures are not necessarily drawn to scale.
  5. You will have 40 minutes working time to complete the test.
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==Problem 1== You can do it!

==Problem 1== You can do it!

Problem 3

You will not be able to cheat on this test, study for this!!

Problem 4

NOOOOO CHEATER CHEATER ONION EATER

Problem 5

bro what happened to problems 1 and 2

Problem 6

4 random points are chosen on a sphere. What is the probability that the tetrahedron with vertices of the 4 points contains the center of the sphere?

(A) 1/2 (B) 1/4 (C) 3/8 (D) 1/8 (E) 3/10 (Source: Putnam) lmao

Problem 8

Alex has 1 apple. Bob has 2 apples. How many apples did their dad eat?

(A) -1 (B) 0 (C) 1 (D) 2 (E) 3

Problem 9

Compute $\frac{1}{0}$.

(A) 1 (C) 5 (B) 2 (D) 6 (E)3

Problem 10

What is the sum of the roots of $\frac{1}{x}$ $+1=x$?

A)0 B)-1 C)1 D)-2 E)2

Problem 11

The equation (2^(333x-2))+(2^(111x+2))=(2^(222x+1))+1 has three real roots. Find their sum. (Source: AIME)


You thought we could let you cheat?

Problem 12

NO CHEATERS!

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Let $(\text{x=2024})$. Compute the last three digits of $((x^3-(x-8)^3)^4-(x-69)^2)^5$?

Problem 18

hi guys. trying to cheat? im ashamed of you code: nsb

Problem 19

Problem 20

Problem 21

this question = 9+10, bc 9+10 = 21

Problem 22

What is the sum of the cubes of the solutions cubed of $x^5+2x^4+3x^3+3x^2+2x+1=0$?

Problem 23

lol we are the defenders against the cheaters... get outta here and study

Problem 24

wait when are the questions coming tho

Problem 25

Did you think you could cheat the AMC ;)

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
2023 AMC 8
Followed by
2025 AMC 8
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All AJHSME/AMC 8 Problems and Solutions