2024 AIME II Problems/Problem 15
Contents
Problem
Find the number of rectangles that can be formed inside a fixed regular dodecagon (-gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles.
Solution 1
By Furaken
There are two kinds of such rectangles: those whose sides are parallel to some edges of the regular 12-gon (Case 1, and those whose sides are not (Case 2).
For Case 1, WLOG assume that the rectangle's sides are horizontal and vertical (don't forget to multiply by 3 at the end of Case 1). Then the rectangle's sides coincide with these segments as shown in the diagram.
We use inclusion-exclusion for this. There are 30 valid rectangles contained in
, as well as 30 in
. However, the 9 rectangles contained in
have been counted twice, so we subtract 9 and we have 51 rectangles in the diagram. Multiplying by 3, we get 153 rectangles for Case 1.
For Case 2, we have this diagram. To be honest, you can count the rectangles here in whatever way you like.
There are 36 rectangles contained within
, and 18 that use points outside
. So we get a total of
rectangles for Case 2.
Adding the two cases together, we get the answer .
Solution 2
Using the same diagram as Solution 1, we can get the number of rectangles from Case 1 by adding the number of rectangles of
and
and then subtracting the overlaps,
We multiply this by 3 to get the total number of rectangles for Case 1, which is 153.
For Case 2, we can first get the total number of rectangles from
then add
and subtract by the overlaps,
Multiply that by 3 and add it to Case 1 to get
.
~pengf
See also
2024 AIME II (Problems • Answer Key • Resources) | ||
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