2014 AMC 12B Problems/Problem 8
Problem
In the addition shown below , , , and are distinct digits. How many different values are possible for ?
Solution
From the first column, we see because it yields a single digit answer. From the fourth column, we see that equals and therefore . We know that . Therefore, the number of values can take is equal to the number of possible sums less than that can be formed by adding two distinct natural numbers. Letting , and letting , we have
Solution (Equation Algorithm)
It is intuitively obvious, even to the most casual observer that the problem statement can be rewritten as:
$10^4A + \10^4B + 10^3B + 10^3C + 10^2B + 10^2A + 10C + 10D + B + A = 10^4D + 10^3B + 10^2D + 10D + D$ (Error compiling LaTeX. Unknown error_msg). This equation can be simplified into:
10^4A + 10^4B + 10^3C + 10^2B + 10^2A + 10C + B + A = 10^4D + 10^2D + D$.
Now from here, it should hopefully make sense that$ (Error compiling LaTeX. Unknown error_msg)A + B = DA + B10^4(A+B) + 10^3C 10^2(A+B) + 10C + (B + A) = 10^4D + 10^2D + D$.
Which equals:$ (Error compiling LaTeX. Unknown error_msg)10^4(D) + 10^3C 10^2(D) + 10C + D = 10^4D + 10^2D + D$.
This simplifies into:$ (Error compiling LaTeX. Unknown error_msg)10^3C + 10C = 0$.
Therefore$ (Error compiling LaTeX. Unknown error_msg)c = 0$.
This means that$ (Error compiling LaTeX. Unknown error_msg)A + B = DD < 10(2, 1)(4, 5)D = 3$$ (Error compiling LaTeX. Unknown error_msg), 4$$ (Error compiling LaTeX. Unknown error_msg), 5$$ (Error compiling LaTeX. Unknown error_msg), 6$$ (Error compiling LaTeX. Unknown error_msg), 7$$ (Error compiling LaTeX. Unknown error_msg), 8$$ (Error compiling LaTeX. Unknown error_msg), 9\boxed{\textbf{(C)}\ 7}$ ~PeterDoesPhysics
See also
2014 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 7 |
Followed by Problem 9 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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