2015 AMC 8 Problems/Problem 1

Problem

Onkon wants to cover his room's floor with his favourite red carpet. How many square yards of red carpet are required to cover a rectangular floor that is $12$ feet long and $9$ feet wide? (There are 3 feet in a yard.)

$\textbf{(A) }12\qquad\textbf{(B) }36\qquad\textbf{(C) }108\qquad\textbf{(D) }324\qquad \textbf{(E) }972$

Solution 1

First, we multiply $12\cdot9$ . To get that, we need $108$ square feet of carpet to cover the room's floor. Since there are $9$ square feet in a square yard, you divide $108$ by $9$ to get $12$ square yards, so our answer is $\bold{\boxed{\textbf{(A)}~12}}$ .

Solution 1.1

You could just leave it as $12\cdot9$ and divide it by $9$ to get $12$ square yards to save some time. This gets us $\bold{\boxed{\textbf{(A)}~12}}$ .

Solution 2

Since there are $3$ feet in a yard, we divide $9$ by $3$ to get $3$ , and $12$ by $3$ to get $4$ . To find the area of the carpet, we then multiply these two values together to get $\boxed{\textbf{(A)}~12}$ .

Video Solution (HOW TO THINK CRITICALLY!!!)

https://youtu.be/8mpjdpKcFs8

~Education, the Study of Everything

Video Solution

https://youtu.be/758_W_eK81g

~savannahsolver

2015 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

Placement:Easy Geometry

Page

Toolbox

Search