2000 AMC 8 Problems/Problem 7
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Problem
What is the minimum possible product of three different numbers of the set ?
Solution
The only way to get a negative product using three numbers is to multiply one negative number and two positives or three negatives. Only two reasonable choices
exist: = (-8)\times(24) = -192
(-8)\times5\times7 = (-8)\times35 = -280
{\text{(B) 7}}$.
See Also
2000 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
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