2003 AMC 10B Problems/Problem 20
Problem
In rectangle and . Points and are on so that and . Lines and intersect at . Find the area of .
Solution
because The ratio of to is since and from subtraction. If we let be the height of
\begin{align*}\frac{2}{5} &= \frac{h}{h+3}\\ 2h+6 &= 5h\\ 3h &= 6\\ h &= 2 (Error compiling LaTeX. Unknown error_msg)
We know the height of is and the base is so the area of is .
See Also
2003 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
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All AMC 10 Problems and Solutions |