2000 AMC 10 Problems/Problem 3

Problem

Each day, Jenny ate $20\%$ of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, $32$ remained. How many jellybeans were in the jar originally?

$\mathrm{(A)}\ 40 \qquad\mathrm{(B)}\ 50 \qquad\mathrm{(C)}\ 55 \qquad\mathrm{(D)}\ 60 \qquad\mathrm{(E)}\ 75$

Solution

$x(.8)(.8)=32$

$x(.64)=32$

$x \cdot \frac{32}{50}=32$

$x=50$

$\boxed{\text{B}}$

2000 AMC 10 (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
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2000 AMC 10 Problems/Problem 3

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