1985 AHSME Problems/Problem 1
Problem 1
If , then
Solution
Solution 1
From , we subtract
from both sides to get
. We can divide both sides now by
to get
. Now we can substitute this into
to get
.
Solution 2
We proceed from as above. Notice that
, so
.
See Also
1985 AHSME (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
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