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1993 AJHSME Problems/Problem 19

Revision as of 19:13, 19 August 2011 by Mrdavid445 (talk | contribs) (Created page with "==Problem== <math>(1901+1902+1903+\cdots + 1993) - (101+102+103+\cdots + 193) = </math> <math>\text{(A)}\ 167,400 \qquad \text{(B)}\ 172,050 \qquad \text{(C)}\ 181,071 \qquad \...")
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Problem

$(1901+1902+1903+\cdots + 1993) - (101+102+103+\cdots + 193) =$

$\text{(A)}\ 167,400 \qquad \text{(B)}\ 172,050 \qquad \text{(C)}\ 181,071 \qquad \text{(D)}\ 199,300 \qquad \text{(E)}\ 362,142$

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