1993 AJHSME Problems/Problem 19
Problem
Solution
We see that , , etc. Each term in the first set of numbers is more than the corresponding term in the second set; Because there are terms in the first set, the expression can be paired up as follows and simplified:
See Also
1993 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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