1994 AJHSME Problems/Problem 10
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Problem
For how many positive integer values of is the expression an integer?
Solution
We should list all the positive divisors of and count them. By trial and error, the divisors of are found to be , for a total of . However, and can't be expressed as for a POSITIVE integer N, so the number of possibilities is .
See Also
1994 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
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