1985 AHSME Problems/Problem 17
Problem
Diagonal of rectangle
is divided into
segments of length
by parallel lines
and
that pass through
and
and are perpendicular to
. The area of
, rounded to the nearest tenth, is
Solution
Let be the intersection of line
and
. Because
is the altitude to the hypotenuse of right triangle
, we have
. Thus,
. Now we use
on
to get
. Now we have to double it to get the area of the entire rectangle:
.
See Also
1985 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
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