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- ...approximately two years, and will be timed to open and self-develop at the correct time. The base will enter the atmosphere of Mars and will use powerful retr19 KB (3,114 words) - 15:24, 16 July 2008
- The addition below is incorrect. The display can be made correct by changing one digit <math>d</math>, wherever it occurs, to another digit ...either a <math>5</math> (no carry) or a <math>6</math> (carry) to create a correct statement.1 KB (223 words) - 13:59, 5 July 2013
- ...of them as soon as the mathematical community had pronounced his solution correct. All but one of these problems had been solved by the meeting in 2000, and13 KB (1,969 words) - 17:57, 22 February 2024
- Michael plays catcher for his school's baseball team. He has always been a great player behind the plate, but this year as a junior, Michael's Joshua finds an answer which Michael confirms is correct. What is Joshua's correct answer (the units digit of <math>2008^{2008}</math>)?71 KB (11,749 words) - 01:31, 2 November 2023
- ...e are what you really need to compile it - the first 2 are to get into the correct folder), in the terminal, run:5 KB (732 words) - 00:47, 13 December 2023
- :Dodecahedron has an error; icosahedron is simply blank. Someone will correct/fill those in eventually - that's why it's a wiki. [[User:Temperal|Temperal806 bytes (113 words) - 22:48, 7 December 2008
- have divided the number by 2 to get the correct answer. What is the correct13 KB (1,821 words) - 22:18, 5 December 2023
- ...ssumes he is the first to arrive. If each takes what he believes to be the correct share of candy, what fraction of the candy goes unclaimed?1 KB (213 words) - 10:16, 4 July 2013
- ...have given up, they turn them in for 4 more. A scoreboard reports how many correct answers various teams have. There are a total of 36 problems, to be complet1 KB (243 words) - 17:53, 1 November 2014
- ...9, but instead, Cindy subtracted 9, then divided by 3, getting 43. If the correct instructions were followed, what would the result be? ..., and <math>R</math> the area of the red square. Which of the following is correct?11 KB (1,733 words) - 11:04, 12 October 2021
- ...}5.5) + (\text{a little})</math>, and as all the options are integers, the correct one is <math>\boxed{\textbf{(C) }6}</math>.1,017 bytes (138 words) - 12:26, 8 November 2021
- ..., and <math>P</math> the area of the red square. Which of the following is correct?2 KB (345 words) - 12:50, 8 November 2021
- ...if he clearly understands what he is doing- just a little mistake) Here is correct soluton:3 KB (581 words) - 02:00, 6 May 2023
- Can someone change this answer so it's correct?3 KB (415 words) - 00:51, 15 September 2023
- Clearly, <math>M = A+C \Longrightarrow</math> the correct answer is <math>\mathrm{(A)}</math>. ...math> which is negative. Thus <math>\mathrm{(A)}</math> is indeed the only correct answer.1 KB (187 words) - 14:29, 5 July 2013
- Only <math>1</math> quantity changes, so the correct answer is <math>\boxed{\text{B}}</math>.1 KB (242 words) - 01:24, 27 July 2023
- ...if one of these is correct, then the other option in its pair must also be correct. There can't be 2 answers. So, the only remaining answer choice is <math>\b2 KB (300 words) - 09:07, 22 January 2023
- This is equal to the area of a small circle, hence the correct answer is <math>\boxed{\text{(B)}\ 1}</math>.2 KB (277 words) - 21:32, 3 July 2013
- ...sts of <math>20</math> questions. The scoring is <math>+5</math> for each correct answer, <math>-2</math> for each incorrect answer, and <math>0</math> for e12 KB (1,568 words) - 09:35, 31 October 2021
- &= 1800 & \text{ Thus \boxed{\text{E}} is the correct answer}1 KB (138 words) - 01:03, 22 January 2020