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  • ...approximately two years, and will be timed to open and self-develop at the correct time. The base will enter the atmosphere of Mars and will use powerful retr
    19 KB (3,114 words) - 15:24, 16 July 2008
  • The addition below is incorrect. The display can be made correct by changing one digit <math>d</math>, wherever it occurs, to another digit ...either a <math>5</math> (no carry) or a <math>6</math> (carry) to create a correct statement.
    1 KB (223 words) - 13:59, 5 July 2013
  • ...of them as soon as the mathematical community had pronounced his solution correct. All but one of these problems had been solved by the meeting in 2000, and
    13 KB (1,969 words) - 17:57, 22 February 2024
  • Michael plays catcher for his school's baseball team. He has always been a great player behind the plate, but this year as a junior, Michael's Joshua finds an answer which Michael confirms is correct. What is Joshua's correct answer (the units digit of <math>2008^{2008}</math>)?
    71 KB (11,749 words) - 01:31, 2 November 2023
  • ...e are what you really need to compile it - the first 2 are to get into the correct folder), in the terminal, run:
    5 KB (732 words) - 00:47, 13 December 2023
  • :Dodecahedron has an error; icosahedron is simply blank. Someone will correct/fill those in eventually - that's why it's a wiki. [[User:Temperal|Temperal
    806 bytes (113 words) - 22:48, 7 December 2008
  • have divided the number by 2 to get the correct answer. What is the correct
    13 KB (1,821 words) - 22:18, 5 December 2023
  • ...ssumes he is the first to arrive. If each takes what he believes to be the correct share of candy, what fraction of the candy goes unclaimed?
    1 KB (213 words) - 10:16, 4 July 2013
  • ...have given up, they turn them in for 4 more. A scoreboard reports how many correct answers various teams have. There are a total of 36 problems, to be complet
    1 KB (243 words) - 17:53, 1 November 2014
  • ...9, but instead, Cindy subtracted 9, then divided by 3, getting 43. If the correct instructions were followed, what would the result be? ..., and <math>R</math> the area of the red square. Which of the following is correct?
    11 KB (1,733 words) - 11:04, 12 October 2021
  • ...}5.5) + (\text{a little})</math>, and as all the options are integers, the correct one is <math>\boxed{\textbf{(C) }6}</math>.
    1,017 bytes (138 words) - 12:26, 8 November 2021
  • ..., and <math>P</math> the area of the red square. Which of the following is correct?
    2 KB (345 words) - 12:50, 8 November 2021
  • ...if he clearly understands what he is doing- just a little mistake) Here is correct soluton:
    3 KB (581 words) - 02:00, 6 May 2023
  • Can someone change this answer so it's correct?
    3 KB (415 words) - 00:51, 15 September 2023
  • Clearly, <math>M = A+C \Longrightarrow</math> the correct answer is <math>\mathrm{(A)}</math>. ...math> which is negative. Thus <math>\mathrm{(A)}</math> is indeed the only correct answer.
    1 KB (187 words) - 14:29, 5 July 2013
  • Only <math>1</math> quantity changes, so the correct answer is <math>\boxed{\text{B}}</math>.
    1 KB (242 words) - 01:24, 27 July 2023
  • ...if one of these is correct, then the other option in its pair must also be correct. There can't be 2 answers. So, the only remaining answer choice is <math>\b
    2 KB (300 words) - 09:07, 22 January 2023
  • This is equal to the area of a small circle, hence the correct answer is <math>\boxed{\text{(B)}\ 1}</math>.
    2 KB (277 words) - 21:32, 3 July 2013
  • ...sts of <math>20</math> questions. The scoring is <math>+5</math> for each correct answer, <math>-2</math> for each incorrect answer, and <math>0</math> for e
    12 KB (1,568 words) - 09:35, 31 October 2021
  • &= 1800 & \text{ Thus \boxed{\text{E}} is the correct answer}
    1 KB (138 words) - 01:03, 22 January 2020

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