2019 AMC 10A Problems/Problem 2
Contents
[hide]Problem
What is the hundreds digit of
Solution
The last three digits of for all are , because there are at least three s and three s in its prime factorization. Because , the answer is .
Solution 2
20 and 15 are both greater than 10, therefore they are divisible by 100 because of powers of 5 and powers of 2, so the hundreds digit is . ~Peppapig_
See Also
2019 AMC 10A (Problems • Answer Key • Resources) | ||
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Followed by Problem 3 | |
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