1997 PMWC Problems/Problem T9
Contents
[hide]Problem
Find the two -digit numbers which become nine times as large if the order of the digits is reversed.
Solution
The pair of numbers are and is .
Notice that the sum of two numbers is 10 times of the smaller one. Let the smaller one be , the large one becomes . Then we have = +. It's obvious that and . Comparing the digits, we have , , , and .
Mistake Above Fix
The actual two numbers are , as mentioned above, but the second number is , not . Someone please fix.
See Also
1997 PMWC (Problems) | ||
Preceded by Problem T8 |
Followed by Problem T10 | |
I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 |