1999 AHSME Problems/Problem 15
Problem
Let be a real number such that . Then
Solution 1 (Fastest)
, so .
Solution 2 (Alternate)
Note that , and since , let and multiply the two, we get . This equates to . Thus, .
See Also
1999 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
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