1967 AHSME Problems/Problem 6

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Problem

If $f(x)=4^x$ then $f(x+1)-f(x)$ equals:

$\text{(A)}\ 4\qquad\text{(B)}\ f(x)\qquad\text{(C)}\ 2f(x)\qquad\text{(D)}\ 3f(x)\qquad\text{(E)}\ 4f(x)$

Solution

The desired expression is equal to $4^{x+1} - 4^{x}$ Using the fact that $4^{x+1}$=$4^{x}*4$, we see that the answer is $3*4^{x}$ $\fbox{D}$

See also

1967 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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