2024 AMC 8 Problems

2024 AMC 8 (Answer Key) Printable versions: Wiki • AoPS Resources • PDF
Instructions This is a 25-question, multiple choice test. Each question is followed by answers marked A, B, C, D and E. Only one of these is correct. You will receive 1 point for each correct answer. There is no penalty for wrong answers. No aids are permitted other than plain scratch paper, writing utensils, ruler, and erasers. In particular, graph paper, compass, protractor, calculators, computers, smartwatches, and smartphones are not permitted. Rules Figures are not necessarily drawn to scale. You will have 40 minutes working time to complete the test.
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==Problem 1== You can do it!

Problem 3

If Bartholomew's pet cat's favourite number in the alphabet is purple, then what is the square root of the combined time in years Bartholomew's father went to get the milk and the time it takes for you to count to 1 million out loud.

Problem 4

Bob has $5$ friends that go to school, only on Tuesday and Wednesday. The chance of rain on Tuesday and Wednesday is $50\%$ . Assuming Bob and his friends are all humans, what is the street number of Bob's house?

$\textbf{(A)}\ 75423 \qquad \textbf{(B)}\ 5987 \qquad \textbf{(C)}\ 491 \qquad \textbf{(D)}\ 653\qquad \textbf{(E)}\ 21574$

Problem 5

bro what happened to problems 1 and 2

Problem 6

4 random points are chosen on a sphere. What is the probability that the tetrahedron with vertices of the 4 points contains the center of the sphere?

(A) 1/2 (B) 1/4 (C) 3/8 (D) 1/8 (E) 3/10 (Source: Putnam) lmao

Problem 8

Alex has 1 apple. Bob has 2 apples. How many apples did their dad eat?

(A) -1 (B) 0 (C) 1 (D) 2 (E) 3

Problem 9

Compute $\frac{1}{0}$ .

(A) 1 (C) 5 (B) 2 (D) 6 (E)3

Problem 10

What is the sum of the roots of $\frac{1}{x}$ $+1=x$ ?

A)0 B)-1 C)1 D)-2 E)2

Problem 11

The equation (2^(333x-2))+(2^(111x+2))=(2^(222x+1))+1 has three real roots. Find their sum. (Source: AIME)

You thought we could let you cheat?

Problem 12

Assuming that $1+1=2$ , then what does $\sqrt{235479^{\sqrt{9472853.23462}\times4912}} + \frac{1}{0}$ equal?

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 1 \qquad \textbf{(D)}\ 256246\qquad \textbf{(E)}\ 10000$

Problem 13

A finite set $S$ of positive integers has the property that, for each $s\in S$ , and each positive integer divisor $d$ of $s$ , there exists a unique element $t \in S$ satisfying $\gcd(s,t)=d$ (the elements $s$ and $t$ could be equal).

Given this information, find all possible values for the number of elements of $S$ . (source: 2021 USAMO)

now that you read this problem you have to do it without looking at the solution or else... let's just say bad things will happen

Problem 14

Problem 15

Let $D$ be an interior point of the acute triangle $ABC$ with $AB > AC$ so that $\angle DAB= \angle CAD$ . The point $E$ on the segment $AC$ satisfies $\angle ADE= \angle BCD$ , the point $F$ on the segment $AB$ satisfies $\angle FDA= \angle DBC$ , and the point $X$ on the line $AC$ satisfies $CX=BX$ . Let $O_1$ and $O_2$ be the circumcentres of the triangles $ADC$ and $EXD$ respectively. Prove that the lines $BC$ , $EF$ , and $O_1 O_2$ are concurrent. (source: 2021 IMO)

now go do this problem as a punishment for trying to cheat

Problem 16

Problem 17

Let . Compute the last three digits of ?

NO CALCULATORS ARE ALLOWED.

Problem 18

hi guys. trying to cheat? im ashamed of you code: nsb

Problem 19

Write your AoPS name here if you took the AMC 8.

Probablity

Problem 20

Find the sum of the square root of -2 and the last digit of pi.

Problem 21

this question = 9+10, bc 9+10 = 21

Problem 22

What is the sum of the cubes of the solutions cubed of $x^5+2x^4+3x^3+3x^2+2x+1=0$ ?

Problem 23

lol we are the defenders against the cheaters... get outta here and study

Problem 24

wait when are the questions coming tho I think it's 1/25 for official answers since all tests end at 1/24

Problem 25

Did you think you could cheat the AMC ;)

and why did you scroll all the way here lol

2024 AMC 8 (Problems • Answer Key • Resources)
Preceded by 2023 AMC 8	Followed by 2025 AMC 8
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All AJHSME/AMC 8 Problems and Solutions

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