1957 AHSME Problems/Problem 18
Problem 18
Circle has diameters
and
perpendicular to each other.
is any chord intersecting
at
.
Then
is equal to:
Solution
Draw . Since
is inscribed on a diameter,
is
. By AA Similarity,
. Setting up ratios, we get
. Cross-multiplying, we get
, so the answer is
.
See Also
1957 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
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