2012 JBMO Problems/Problem 2
Problem
Let the circles and intersect at two points and , and let be a common tangent of and that touches and at and respectively. If and , evaluate the angle .
Solution
Let and be the centers of circles and respectively. Also let be the intersection of and line .
Note that is perpendicular to since is a tangent of . In order for to be perpendicular to , must be the point diametrically opposite . Note that is a right angle since it inscribes a diameter. By AA similarity, . This gives that .
By Power of a Point on point with respect to circle , we have that . Using Power of a Point on point with respect to circle gives that . Therefore and . Since , . We now see that is a triangle. Since it is similar to , .
Solution by Someonenumber011 :)
The last paragraph is basically using the fact that lies on the radical axis of and .
2012 JBMO (Problems • Resources) | ||
Preceded by 2011 JBMO |
Followed by 2013 JBMO | |
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