1997 AHSME Problems/Problem 15
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Problem
Medians and
of triangle
are perpendicular,
, and
. The area of triangle
is
Solution
One median divides a triangle into equal areas, so all three medians will divide a triangle into
equal areas.
The median is divided into a
ratio at centroid
, so
Similarly,
The area of the right triangle is
The area of the whole figure is , and the correct answer is
.
See also
1997 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
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