2003 AMC 10B Problems/Problem 8

Problem

The second and fourth terms of a geometric sequence are $2$ and $6$ . Which of the following is a possible first term?

$\textbf{(A) } -\sqrt{3} \qquad\textbf{(B) } -\frac{2\sqrt{3}}{3} \qquad\textbf{(C) } -\frac{\sqrt{3}}{3} \qquad\textbf{(D) } \sqrt{3} \qquad\textbf{(E) } 3$

Solution

Let the first term be $a$ and the common difference be $r$ . Therefore,

$ar=2$ (1)

and

$ar^3=6$ . (2)

Dividing (2) by (1) eliminates the $a$ , yielding $r^2=3$ , so $r=\pm\sqrt{3}$ .

Now, since $ar=2$ , $a=\frac{2}{r}$ , so $a=\frac{2}{\pm\sqrt{3}}=\pm\frac{2\sqrt{3}}{3}$ .

We therefore see that $\boxed{\text{B}}$ is a possible first term.

2003 AMC 10B (Problems • Answer Key • Resources)
Preceded by Problem 7	Followed by Problem 9
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

Page

Toolbox

Search

2003 AMC 10B Problems/Problem 8

Problem

Solution

See Also