2003 AMC 8 Problems/Problem 19

Solution

Find the least common multiple of $15, 20, 25$ by turning the numbers into their prime factorization. $15 = 3 * 5, 20 = 2^2 * 5, 25 = 5^2$ Gather all necessary multiples $3, 2^2, 5^2$ when multiplied gets $300$ . The multiples of $300 - 300, 600, 900, 1200, 1500, 1800, 2100$

$\boxed{\textbf{(C)}\ 3}$

2003 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 18	Followed by Problem 20
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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2003 AMC 8 Problems/Problem 19

Solution