1984 AHSME Problems/Problem 28
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Problem
The number of distinct pairs of integers such that and is
Solution
We can simplify to . Therefore, the only solutions are such that and . The only solutions to this are . Each of these gives distinct pairs of , so there are pairs, .
See Also
1984 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 27 |
Followed by Problem 29 | |
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