2013 AMC 8 Problems/Problem 7
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[hide]Problem
Trey and his mom stopped at a railroad crossing to let a train pass. As the train began to pass, Trey counted 6 cars in the first 10 seconds. It took the train 2 minutes and 45 seconds to clear the crossing at a constant speed. Which of the following was the most likely number of cars in the train?
Solution 1
If Trey saw , then he saw .
2 minutes and 45 seconds can also be expressed as seconds.
Trey's rate of seeing cars, , can be multiplied by on the top and bottom (and preserve the same rate):
. It follows that the most likely number of cars is .
Solution 2
minutes and seconds is equal to .
Since Trey probably counts around cars every seconds, there are $\floor{\dfrac{165}{10}}=16$ (Error compiling LaTeX. Unknown error_msg) groups of cars that Trey most likely counts. Since , the closest answer choice is .
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
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All AJHSME/AMC 8 Problems and Solutions |
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