2012 AMC 10B Problems/Problem 19
Problem
In rectangle ,
,
, and
is the midpoint of
. Segment
is extended 2 units beyond
to point
, and
is the intersection of
and
. What is the area of
?
Solution
The easiest way to find the area would be to find the area of and subtract the areas of
and
You can easily get the area of
because you know
and
, so
's area is
. However, for triangle
you don't know
However, you can note that triangle
is similar to triangle
through AA. You see that
So, You can do
for
and
Now, you can find the area of
which is
Now, you do
which is answer choice (C).
See Also
2012 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 18 |
Followed by Problem 20 | |
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All AMC 10 Problems and Solutions |
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