1991 AHSME Problems/Problem 14
Problem
If is the cube of a positive integer and
is the number of positive integers that are divisors of
, then
could be
(A) (B)
(C)
(D)
(E)
Solution 1: Number Sense
Solution by e_power_pi_times_i
Notice that if is expressed in the form
, then the number of positive divisors of
is
. Checking through all the answer choices, the only one that is in the form
is
.
Solution 2: Answer Choices
Solution by e_power_pi_times_i
Since the divisors are from , then the answer must be something in
. Since
and
are the same
, as well as
and
,
is the only answer left.
See also
1991 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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