2016 AMC 8 Problems/Problem 8
Find the value of the expression
Solution
We can group each subtracting pair together: After subtracting, we have: There are even numbers, therefore there are even pairs. Therefore the sum is
Solution 2
Since our list does not start at one, we divide every number by 2 and we end up with We can group each subtracting pair together: As we can see, the list now starts at 1 and ends at 50, thus there are 50 numbers in total. Since all the subtracting pairs are equal to one, the solution equals .
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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