1985 AHSME Problems/Problem 21

Revision as of 00:06, 3 April 2018 by Hapaxoromenon (talk | contribs) (Fixed a typo)

Problem

How many integers $x$ satisfy the equation $(x^2-x-1)^{x+2}=1?$

$\mathrm{(A)\ } 2 \qquad \mathrm{(B) \ }3 \qquad \mathrm{(C) \  } 4 \qquad \mathrm{(D) \  } 5 \qquad \mathrm{(E) \  }\text{none of these}$

Solution

Notice that any power of $1$ is $1$, so $x^2-x-1=1$ would give valid solutions.

$x^2-x-2=0$

$(x-2)(x+1)=0$

$x=2, -1$

Also, $-1$ to an even power also gives $1$, so we check $x^2-x-1=-1$

$x^2-x=0$

$x(x-1)=0$

$x=0, 1$

However, $x=1$ gives an odd power of $-1$, so this is discarded. Finally, notice that anything to the $0\text{th}$ power (except for $0$, as $0^0$ is undefined) gives $1$.

$x+2=0$

$x=-2$

This doesn't make $x^2-x-1=0$, so this is also valid.

Overall, our valid solutions are $x=-2, -1, 0, 2$ for a grand total of $4, \boxed{\text{C}}$.

See Also

1985 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 20
Followed by
Problem 22
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png