1960 AHSME Problems/Problem 13
Problem
The polygon(s) formed by , and , is (are):
Solution
The points of intersection of two of the lines are and , so use the Distance Formula to find the sidelengths.
Two of the side lengths are while one of the side lengths is . That makes the triangle isosceles, so the answer is .
See Also
1960 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
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