Difference between revisions of "1951 AHSME Problems/Problem 6"

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Mr. A owns a home worth $10000. He sells it to Mr. B at a 10% profit based on the worth
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== Problem ==
of the house. Mr. B sells the house back to Mr. A at a 10% loss. Then:
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The bottom, side, and front areas of a rectangular box are known. The product of these areas
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is equal to:
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<math> \textbf{(A)}\ \text{the volume of the box} \qquad\textbf{(B)}\ \text{the square root of the volume} \qquad\textbf{(C)}\ \text{twice the volume}</math>
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<math> \textbf{(D)}\ \text{the square of the volume} \qquad\textbf{(E)}\ \text{the cube of the volume}</math>
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== Solution ==
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Let the length of the edges of this box have lengths <math>a</math>, <math>b</math>, and <math>c</math>. We're given <math>ab</math>, <math>bc</math>, and <math>ca</math>. The product of these values is <math>a^2b^2c^2</math>, which is the square of the volume of the box. <math>\boxed{\textbf{(D)}}</math>
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== See Also ==
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{{AHSME 50p box|year=1951|num-b=5|num-a=7}}
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[[Category:Introductory Geometry Problems]]
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{{MAA Notice}}

Latest revision as of 12:20, 5 July 2013

Problem

The bottom, side, and front areas of a rectangular box are known. The product of these areas is equal to:

$\textbf{(A)}\ \text{the volume of the box} \qquad\textbf{(B)}\ \text{the square root of the volume} \qquad\textbf{(C)}\ \text{twice the volume}$ $\textbf{(D)}\ \text{the square of the volume} \qquad\textbf{(E)}\ \text{the cube of the volume}$

Solution

Let the length of the edges of this box have lengths $a$, $b$, and $c$. We're given $ab$, $bc$, and $ca$. The product of these values is $a^2b^2c^2$, which is the square of the volume of the box. $\boxed{\textbf{(D)}}$

See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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All AHSME Problems and Solutions

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