Difference between revisions of "1954 AHSME Problems/Problem 8"
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Revision as of 14:05, 6 June 2016
Problem 8
The base of a triangle is twice as long as a side of a square and their areas are the same. Then the ratio of the altitude of the triangle to the side of the square is:
Solution
Let the base and altitude of the triangle be , the common area , and the side of the square . Then , so