1954 AHSME Problems/Problem 8
Problem 8
The base of a triangle is twice as long as a side of a square and their areas are the same. Then the ratio of the altitude of the triangle to the side of the square is:
Solution
Let the base and altitude of the triangle be , the common area , and the side of the square . Then , so
See Also
1954 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
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