Difference between revisions of "1960 AHSME Problems/Problem 2"

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Latest revision as of 12:47, 20 December 2018

Problem

It takes $5$ seconds for a clock to strike $6$ o'clock beginning at $6:00$ o'clock precisely. If the strikings are uniformly spaced, how long, in seconds, does it take to strike $12$ o'clock?

$\textbf{(A)}9\frac{1}{5}\qquad \textbf{(B )}10\qquad \textbf{(C )}11\qquad \textbf{(D )}14\frac{2}{5}\qquad \textbf{(E )}\text{none of these}$

Solution

Between six strikes, there are five intervals of space. Since it takes five seconds total, each interval is one second long. Therefore, $12$ strikes will take $11$ seconds. $\boxed{\textbf{(C)}}$.

See Also

1960 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AHSME Problems and Solutions