# 1960 AHSME Problems/Problem 3

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## Problem

Applied to a bill for $\textdollar{10,000}$ the difference between a discount of $40$% and two successive discounts of $36$% and $4$%, expressed in dollars, is:

$\textbf{(A)}0\qquad \textbf{(B)}144\qquad \textbf{(C)}256\qquad \textbf{(D)}400\qquad \textbf{(E)}416$

## Solution

Taking the discount of $40$% means you're only paying $60$% of the bill. That results in $10,000\cdot0.6=\textdollar{6,000}$.

Likewise, taking two discounts of $36$% and $4$% means taking $64$% of the original amount and then $96$% of the result. That results in $10,000\cdot0.64\cdot0.96=\textdollar{6,144}$.

Taking the difference results in $6,144-6,000=\textdollar{144}$, or answer choice $\boxed{\textbf{(B)}}$.

## See Also

 1960 AHSC (Problems • Answer Key • Resources) Preceded byProblem 2 Followed byProblem 4 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 All AHSME Problems and Solutions
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